Br[C:2]1[CH:3]=[CH:4][C:5]2[C:9]3[CH:10]=[CH:11][CH:12]=[CH:13][C:8]=3[S:7][C:6]=2[CH:14]=1.[CH3:15][Sn:16](C)([CH3:39])[C:17]1C=CC2C3C=CC(CO[Si](C(C)(C)C)(C)C)=CC=3OC=2C=1>>[CH3:15][Sn:16]([CH3:39])([CH3:17])[C:2]1[CH:3]=[CH:4][C:5]2[C:9]3[CH:10]=[CH:11][CH:12]=[CH:13][C:8]=3[S:7][C:6]=2[CH:14]=1Using the procedure described in Example 316, but substituting 3-bromodibenzothiophene for the bromodibenzofuran 10 of Example 316, provided the title compound in 82% yield.
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