[F:1][C:2]([F:16])([F:15])[CH2:3][NH:4][C:5]1[CH:14]=[CH:13][C:8]([C:9]([O:11]C)=[O:10])=[CH:7][CH:6]=1.CO.[OH-].[K+]>O>[F:1][C:2]([F:15])([F:16])[CH2:3][NH:4][C:5]1[CH:6]=[CH:7][C:8]([C:9]([OH:11])=[O:10])=[CH:13][CH:14]=1step d—To a solution of 124 (0.349 g, 1.497 mmol), MeOH (3 mL), H2O (1 mL) was added KOH (0.420 g, 7.48 mmol) and the resulting solution was heated at reflux for 1 h. The MeOH was evaporated and the residue diluted with H2O (15 mL) and acidified to pH of 2 with 6N HCl. The white precipitate was filtered, washed with H2O and air dried to afford 0.278 g (85%) of 126.
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