NC1C=CC(C)=C(C(C2C=CC(NC3C=CC(C(F)(F)F)=CC=3)=CC=2Cl)=O)C=1.[Cl:29][C:30]1[CH:35]=[C:34]([NH:36][C:37]2[CH:42]=[CH:41][C:40]([F:43])=[CH:39][C:38]=2[Cl:44])[CH:33]=[CH:32][C:31]=1[C:45]([C:47]1[CH:52]=[C:51]([N+:53]([O-])=O)[CH:50]=[CH:49][C:48]=1[CH3:56])=[O:46]>>[NH2:53][C:51]1[CH:50]=[CH:49][C:48]([CH3:56])=[C:47]([C:45]([C:31]2[CH:32]=[CH:33][C:34]([NH:36][C:37]3[CH:42]=[CH:41][C:40]([F:43])=[CH:39][C:38]=3[Cl:44])=[CH:35][C:30]=2[Cl:29])=[O:46])[CH:52]=1The reaction was carried out similarly as described in the preparation of compound 415, using compound 420 (0.21 mmol). The crude product was used without any further purification.
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