[Cl:1][C:2]1[CH:7]=[CH:6][C:5]([C:8]2[C:12]([C:13]([OH:15])=[O:14])=[C:11](C(O)=O)[S:10][N:9]=2)=[CH:4][CH:3]=1>ClC1C=CC=CC=1Cl>[Cl:1][C:2]1[CH:3]=[CH:4][C:5]([C:8]2[C:12]([C:13]([OH:15])=[O:14])=[CH:11][S:10][N:9]=2)=[CH:6][CH:7]=1Into a 50-mL round-bottom flask, was placed 3-(4-chlorophenyl)-1,2-thiazole-4,5-dicarboxylic acid (1.8697 g, 6.74 mmol, 1.00 equiv), 1,2-dichlorobenzene (20 mL). The resulting solution was stirred for 20 min at 200° C. The resulting mixture was concentrated, and then added 30 mL of petroleum ether slowly when it is hot. The solids were collected by filtration, washed with petroleum ether. This resulted in 1.35 g (86%) of 3-(4-chlorophenyl)-1,2-thiazole-4-carboxylic acid as a white solid.
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