[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([S:8][C:9]2[CH:14]=[CH:13][C:12]([CH3:15])=[CH:11][CH:10]=2)=[C:4]([N+:16]([O-])=O)[CH:3]=1.Cl[Sn]Cl>>[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([S:8][C:9]2[CH:14]=[CH:13][C:12]([CH3:15])=[CH:11][CH:10]=2)=[C:4]([NH2:16])[CH:3]=1The product from Example 47a was reduced with SnCl2 following the procedure from Example 1f giving the title compound.
読み込み中…