[CH3:1][C:2]1[CH:8]=[CH:7][C:5]([NH2:6])=[CH:4][CH:3]=1.[N+:9]([C:12]1[CH:20]=[CH:19][CH:18]=[CH:17][C:13]=1[C:14](Cl)=[O:15])([O-:11])=[O:10]>>[N+:9]([C:12]1[CH:20]=[CH:19][CH:18]=[CH:17][C:13]=1[C:14]([NH:6][C:5]1[CH:7]=[CH:8][C:2]([CH3:1])=[CH:3][CH:4]=1)=[O:15])([O-:11])=[O:10]Using the procedure described in Example 93, Part A, 4-methylaniline (9.3 mmol) and 2-nitrobenzoyl chloride (10.3 mmol) yielded 1.55 g (65%) of the title compound.
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