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HRID 461462作成日:2026年10月27日

Sodium hydride → 1-[2,4-Dichloro-beta-(4-thiazolylmethoxy) phenethyl]imidazole hydrochloride

https://huagongshe.com/reaction/461462

反応式

関与物質

役割名称HCID仕込み量
反応物Sodium hydrideHCID 24758—
反応物(+-)-alpha-(2,4-Dichlorophenyl)-1H-imidazole-1-ethanolHCID 32238—
反応物4-(Chloromethyl)-1,3-thiazoleHCID 2763290—
溶媒WaterHCID 962—
溶媒TetrahydrofuranHCID 8028—
生成物1-[2,4-Dichloro-beta-(4-thiazolylmethoxy) phenethyl]imidazole hydrochlorideHCID 8673528192.6%

反応条件

温度70 °C

反応手順

A solution of 1-(2,4-dichloro-phenyl)-2-(1-imidazolyl) ethanol (2.4 g, 9.4 mmole) in dry tetrahydrofuran (20 ml) was added to sodium hydride (0.62 g, as an 80% dispersion in oil, 0.02 mole) and warmed at 70° C for 90 minutes. The solution was cooled to 0° C and 4-chloromethylthiazole (1.5 g, 11.2 mmole), dissolved in a little dry tetrahydrofuran, was added. The mixture was stirred at 0° C for 1 hour and at room temperature for 6 hours. Further 4-chloromethylthiazole (0.25 g) was added and the stirring continued for 36 hours. The reaction mixture was then diluted with water (70 ml) and extracted several times with ether. The ether extracts were combined, dried over MgSO4 and evaporated. The oily residue was taken up in dry ether (50 ml) and treated with a solution of HCl in ether. The solid precipitate was collected and recrystallized from a mixture of methanol and di-isopropyl ether to give 1-[2,4-dichloro-β-(4-thiazolylmethoxy) phenethyl]imidazole hydrochloride (1.7 g, 46%) m.p. 183°-184°. (Found: C, 46.3; H, 3.7; N, 10.7. C15H13N3Cl2OS.HCl requires C, 46.1; H, 3.6; N, 10.7%).

情報源と証拠

DOI10.6084/m9.figshare.5104873.v1
特許番号US04062966
出典データセットuspto-grants-1977_12
ORD IDord-def45323cb3d433197a0a26f4a50ada9
出典メモuspto-grants-1977_12