[F:1][C:2]1[CH:3]=[C:4]([OH:11])[CH:5]=[CH:6][C:7]=1[N+:8]([O-:10])=[O:9].[F:12][C:13]([F:17])=[C:14]([F:16])[F:15].C1(O)C=CC=CC=1.[OH-].[K+]>O1CCOCC1.O>[F:1][C:2]1[CH:3]=[C:4]([O:11][C:14]([F:16])([F:15])[CH:13]([F:17])[F:12])[CH:5]=[CH:6][C:7]=1[N+:8]([O-:10])=[O:9]
After dissolving 1.15 g of 3-fluoro-4-nitrophenol in 10 ml of dioxane, the resulting solution was violently stirred at about 60° C. for 15 minutes under the stream of a tetrafluoroethylene gas in large excess of said phenol. After quickly adding 0.04 g of potassium hydroxide, the solution was violently stirred for 2 hours under the same condition. The reaction solution was cooled, and after adding water, extracted with two 100-ml portions of diethyl ether. The ether layers were combined, dried and concentrated to obtain a yellow oily product as a residue. This oily product was subjected to chromatography on silica gel to obtain 0.20 g of 2-fluoro-4-(1,1,2,2-tetrafluoroethoxy)nitrobenzene.
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