[Br:1][C:2]1[CH:10]=[CH:9][CH:8]=[CH:7][C:3]=1[C:4]([OH:6])=[O:5].C([O-])([O-])=O.[K+:15].[K+]>CO>[K+:15].[Br:1][C:2]1[CH:10]=[CH:9][CH:8]=[CH:7][C:3]=1[C:4]([O-:6])=[O:5]To a solution of o-bromobenzoic acid (201.03 g, 1.0 mol) in MeOH (500 mL), K2CO3 (69 g, 1.0 mol) was added. The mixture was concentrated to give the desired product (239.1 g, 1.0 mol, 100%).
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