Stannous Chloride → 6-Fluoroquinolin-8-amine
反応式
[F:1][C:2]1[CH:3]=[C:4]2[C:9](=[C:10]([N+:12]([O-])=O)[CH:11]=1)[N:8]=[CH:7][CH:6]=[CH:5]2.[Sn](Cl)Cl>Cl>[F:1][C:2]1[CH:3]=[C:4]2[C:9](=[C:10]([NH2:12])[CH:11]=1)[N:8]=[CH:7][CH:6]=[CH:5]2参加物
4
実験手順
In a similar fashion using route 1 general procedure 4, 6-fluoro-8-nitroquinoline (Intermediate 36) (1.0 g, 5.41 mmol), tin (II) chloride (3.08 g, 16.2 mmol) and 6N HCl (5 drops) gave the title compound (650 mg, 74%) which was used in the next step without further purification.
出典と根拠
- ORDレコード
- ord-c5a649fabcfb4a2fbff7a40b2275815b
- 出典データセット
- uspto-grants-2015_08
- 特許番号
- US09102688B2
反応ノート
読み込み中…