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HRID 561423作成日:2026年10月27日

1-Bromo-4-fluorobenzene → (4-Chloro-2-fluorophenyl)(4-fluorophenyl)methanol

https://huagongshe.com/reaction/561423

反応式

関与物質

役割名称HCID仕込み量
反応物1-Bromo-4-fluorobenzeneHCID 9993—
反応物alpha-(4-Fluorophenyl)-4-(trifluoromethyl)benzenemethanolHCID 579773—
反応物4-Chloro-2-fluorobenzaldehydeHCID 2724908—
生成物(4-Chloro-2-fluorophenyl)(4-fluorophenyl)methanolHCID 58392437—

反応手順

The title compound was prepared starting from 4.60 g (26.28 mmol) of 4-bromofluorobenzene and 5.00 g (31.53 mmol) of 4-chloro-2-fluorobenzaldehyde in analogy to the synthesis of the compound from Example 80A. 4.45 g (66% of theory) of the title compound were obtained.

情報源と証拠

DOI10.6084/m9.figshare.5104873.v1
特許番号US08063234B2
出典データセットuspto-grants-2011_11
ORD IDord-4eb600ba820a4f04a7489fc54f54436b
出典メモuspto-grants-2011_11