Isopropanol → 6-(3-Methoxyphenyl)-4-Propylmorpholin-3-one

HRID 600222ノート

反応式

HRID 600222 の反応式
[OH-].[K+].C(O)(C)C.Cl[CH2:8][C:9]([N:11]([CH2:15][CH:16]([OH:25])[C:17]1[CH:22]=[CH:21][CH:20]=[C:19]([O:23][CH3:24])[CH:18]=1)[CH2:12][CH2:13][CH3:14])=[O:10]>O>[CH3:24][O:23][C:19]1[CH:18]=[C:17]([CH:16]2[CH2:15][N:11]([CH2:12][CH2:13][CH3:14])[C:9](=[O:10])[CH2:8][O:25]2)[CH:22]=[CH:21][CH:20]=1

参加物

5

実験手順

Potassium hydroxide (4.2 g 0.07 mol), isopropyl alcohol (500 ml) and the amide from example 4 (17.8 g, 0.06 mol were stirred together as an opaque solution with water (15 ml) for 2 hours. The reaction mixture was concentrated in vacuo and the yellow residue dissolved in ethyl acetate (200 ml). This was partitioned with water (200 ml) then brine (200 ml). The organic fraction was dried over anhydrous magnesium sulphate, filtered and concentrated in vacuo to give the title compound as a yellow oil (15.8 g, 0.06 mol, 100%). 1H NMR (CDCl3, 400 MHz) δ: 0.96 (t, 3H), 1.62 (m, 2H), 3.36 (m, 2H), 3.51 (q, 2H), 3.81 (s, 3H), 4.30-4.62 (bq, 2H), 4.79 (d, 1H), 6.85 (d, 1H), 6.91 (d, 1H), 6.95 (s, 1H), 7.29 (t, 1H). LRMS: m/z 272. Analysis found C, 66.80; H, 7.78; N, 5.52%. C14H19NO30.1H2O requires C, 66.96; H, 7.71; N, 5.58%.

後処理

  1. concentrationThe reaction mixture was concentrated in vacuo
  2. dissolutionthe yellow residue dissolved in ethyl acetate (200 ml)
  3. customThis was partitioned with water (200 ml)
  4. dry with materialThe organic fraction was dried over anhydrous magnesium sulphate
  5. filtrationfiltered
  6. concentrationconcentrated in vacuo

出典と根拠

ORDレコード
ord-386b143dfbdb4a9ea77f348549c58094
出典データセット
uspto-grants-2011_03
特許番号
US07902188B2

反応ノート

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