COC(=O)/[CH:4]=[CH:5]\[C:6]1[CH:11]=[CH:10][C:9]([Br:12])=[CH:8][CH:7]=1.[CH3:14][CH2:15][O:16][C:17]([CH3:19])=[O:18]>>[CH2:15]([O:16][C:17]([C@@H:19]1[CH2:4][C@@H:5]1[C:6]1[CH:11]=[CH:10][C:9]([Br:12])=[CH:8][CH:7]=1)=[O:18])[CH3:14]Prepared according to the procedure described in Example 42, Step 1, but using Z-3-(4-Bromo-phenyl)-acrylic acid methyl ester from Step 1 as starting material Flash chromatography (Hex:EtOAc 85:15) afforded the title compound as a oil.
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