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HRID 1031591생성일: 2026년 10월 26일

2-Bromoethanol → 2-Bromoethyl 2-carboxyphenylacetate

https://huagongshe.com/reaction/1031591

반응식

참여 물질

역할이름HCID투입량
반응물2-BromoethanolHCID 10898—
반응물Phosphorus pentachlorideHCID 24819—
반응물Homophthalic acidHCID 66643—
반응물2-Bromoethyl 2-carboxyphenylacetateHCID 15052426—
촉매Sulfuric AcidHCID 1118—
용매BenzeneHCID 241—
생성물2-Bromoethyl 2-carboxyphenylacetateHCID 1505242664%
생성물4-Chloro-3-[2-bromoethyl]-isocoumarinHCID 2147113846%

반응 단계

2-Bromoethyl 2-carboxyphenylacetate was prepared from heating 10 g of homophthalic acid (56 mmole) and 21 g of 2-bromoethanol (167 mmole) in 175 ml of benzene with a few drops of conc. sulfuric acid at 90°-110° C. for two hours, yield 64%. TLC shows that it is a pure compound. The cyclization of 2-bromoethyl 2-carboxyphenylacetate with PCl5 was performed by a previous method with modification (Tirodkar, and Usgaonkar, Indian. J. Chem. 7, pp 114-1116 (1969)). 1.15 g of 2-bromoethyl 2-carboxyphenylacetate was heated with 2.1 g of PCl5 in 90 ml of benzene at 70° C. for 2 hrs. The benzene was removed and the residue triturated with petroleum ether. The crude product was purified by silica gel column chromatography with methylene chloride as an eluent to give 560 mg of 3-(bromoethyl)-4-chloroisocoumarin (yield, 46%). IR and NMR spectra show it was the desired product. 100 mg of 3-bromoethyl-4-chloroisocoumarin (0.3 mmole) was heated with 60 mg of thiourea (0.8 mmole) in 5 ml of THF at 70° C. for 2 days to give a yellow solid, 50 mg (yield, 40%), m.p. 167°-169° C. (dec); one spot on TLC, RF=0.7 (Butanol:acetic acid:water=6:1:5); NMR spectrum (d6 -DMSO), δ9.1 (2b, 4H), 7.5-8.1 (m, 4H), 4.6 (t, 2H), 3.6 (t, 2H); mass spectrum (FAB+), m/e=299 (M+ -Br). Anal. Calc. for C12H12N2O3Br1Cl1S2 : C, 37.96; H, 3.19; N, 7.38. Found: C, 37.81; H, 3.28; N, 7.71.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US04954519
출처 데이터셋uspto-grants-1990_09
ORD IDord-0b88f404bc0b40d2a8747a7bc0d2bbd4
출처 메모uspto-grants-1990_09