Chlorine → 2-methyl-4,5-bis(methylsulfonyl)benzoic Acid
반응식
ClCl.[CH3:3][C:4]1[CH:12]=[C:11](Cl)[C:10]([S:14]([CH3:17])(=[O:16])=[O:15])=[CH:9][C:5]=1[C:6]([OH:8])=[O:7]>B(O[O-])=O.[Na+]>[CH3:3][C:4]1[CH:12]=[C:11]([S:14]([CH3:10])(=[O:16])=[O:15])[C:10]([S:14]([CH3:17])(=[O:16])=[O:15])=[CH:9][C:5]=1[C:6]([OH:8])=[O:7]참가 물질
4
실험 절차
in stage c) the chlorine substituent is converted into a second methylsulfonyl group by reacting 2-methyl-4-chloro-5-methylsulfonylbenzoic acid with sodium methylthiolate and then oxidizing the thioether with an oxidizing agent, in particular sodium perborate, to give the corresponding intermediate 2-methyl-4,5-di(methylsulfonyl)benzoic acid,
출처 및 근거
- ORD 기록
- ord-46f227b4b1ca4b0abdffbf2b3e04ef28
- 출처 데이터셋
- uspto-grants-2003_02
- 특허 번호
- US06515143B2
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