Sodium Hydroxide → Monooctyl tin tris(isooctylthioglycolate)

참여 물질

반응 단계

Monooctyltin trichloride, 338.3 grams (1.0 mole), was added to a solution of 120.0 grams (3.0 moles) sodium hydroxide in 700 ml water, in a suitable reaction vessel, at such a rate that the exothermic reaction could be controlled at or below 75° C. This was followed by addition of 622.5 grams (3.0 moles) of isooctylthioglycolate. On continued stirring at or below 75° C., the reaction was deemed complete when all solid dioctyltin oxide hd been consumed. The resulting mixture was allowed to phase split. After discharging the aqueous by-product, vacuum stripping and filtering the resulting oily liquid, 851.2 grams of monooctyl tin tris(isooctylthioglycolate) was obtained.

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