Bromine → 4-Chlorophthalic anhydride

반응식

[Cl:1][CH:2]1[CH:12]=[CH:11][CH:5]2[C:6]([O:8][C:9](=[O:10])[CH:4]2[CH2:3]1)=[O:7].BrBr>>[Cl:1][C:2]1[CH:3]=[C:4]2[C:9](=[O:10])[O:8][C:6](=[O:7])[C:5]2=[CH:11][CH:12]=1

참가 물질

반응물 2

HCID 24408Bromine

HCID 54187688HCID 54187688, 화합물

생성물 1

HCID 670444-Chlorophthalic anhydride

실험 절차

A co-pending application, Ser. No. 07/405,606, discloses that 4-chlorotetrahydrophthalic anhydride reacts with elemental bromine to form 4-chlorophthalic anhydride. 4-Bromophthalic anhydride is sometimes found as a side product in low percentage, but is not economically recoverable.

출처 및 근거

ORD 기록: ord-cc51c67f4bbe4d78b1a4d1e5cf37cc2b
출처 데이터셋: uspto-grants-1990_10
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US04962206

반응 노트

불러오는 중…