반응식
F[C:2]1[CH:7]=[CH:6][C:5]([C:8]([F:11])([F:10])[F:9])=[CH:4][CH:3]=1.C[O:13][C:14](=[O:22])[C:15]1[CH:20]=[CH:19][C:18]([OH:21])=[CH:17][CH:16]=1>>[F:9][C:8]([F:11])([F:10])[C:5]1[CH:6]=[CH:7][C:2]([O:21][C:18]2[CH:19]=[CH:20][C:15]([C:14]([OH:22])=[O:13])=[CH:16][CH:17]=2)=[CH:3][CH:4]=1참가 물질
3
실험 절차
4-(4-Trifluoromethyl-phenoxy)benzoic acid (474 mg, 80%) was prepared from 1-fluoro-4-trifluoromethyl benzene (328 mg, 2.0 mmol) and 4-hydroxy benzoic acid methyl ester (304 mg, 2.0 mmol) following general procedure B, then hydrolyzed following general procedure C to give the corresponding acid (450 mg, 80%). 3-(4′-Trifluoromethyl-biphenyl-4-yl)-(2S)-[4-(4-trifluoromethyl-phenoxy)-benzoylamino]-propionic acid methyl ester (121 mg, 82%) was prepared starting from the above acid (70 mg, 0.25 mmol) and 2-amino-3-(4′-trifluoromethyl-biphenyl-4-yl)-(2S)-propionic acid methyl ester (108 mg, 0.30 mmol) according to general procedure A. The ester was hydrolyzed following general procedure C to give the title compound (105 mg, 89%)
출처 및 근거
- ORD 기록
- ord-6ed3f8eb4b77479ca5ea6dafff5c3d3b
- 출처 데이터셋
- uspto-grants-2006_10
- 특허 번호
- US07122580B2
연결된 노트
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