Dimethylamine → 2-Methoxy-benzylidene-dimethyl-ammonium chloride

반응식

[CH3:1][NH:2][CH3:3].[CH3:4][O:5][C:6]1[CH:13]=[CH:12][CH:11]=[CH:10][C:7]=1[CH:8]=O.C([Cl:17])(=O)C>>[Cl-:17].[CH3:4][O:5][C:6]1[CH:13]=[CH:12][CH:11]=[CH:10][C:7]=1[CH:8]=[N+:2]([CH3:3])[CH3:1]

참가 물질

반응물 3

HCID 674Dimethylamine

HCID 6367Acetyl chloride

HCID 86582-Methoxybenzaldehyde

생성물 1

HCID 219853032-Methoxy-benzylidene-dimethyl-ammonium chloride

실험 절차

The reaction of 17.0 ml (0.135 mol) dimethylamine solution and 6.8 ml (0.050 mol) 2-methoxybenzaldehyde in accordance with general synthesis instructions 1 and subsequent reaction with 3.0 ml (0.050 mol) acetyl chloride in accordance with general synthesis instructions 3 gave 4.8 g (corresponding to 48% of the yield calculated by theory) (2-methoxy-benzylidene)-dimethyl-ammonium chloride.