Sodium ethoxide → 6-Iodo-4-ethoxy-quinoline-3-carboxylic acid ethyl ester
반응식
[CH2:1]([O:3][C:4]([C:6]1[CH:7]=[N:8][C:9]2[C:14]([C:15]=1Cl)=[CH:13][C:12]([I:17])=[CH:11][CH:10]=2)=[O:5])[CH3:2].[O-:18][CH2:19][CH3:20].[Na+]>C(O)C>[CH2:1]([O:3][C:4]([C:6]1[CH:7]=[N:8][C:9]2[C:14]([C:15]=1[O:18][CH2:19][CH3:20])=[CH:13][C:12]([I:17])=[CH:11][CH:10]=2)=[O:5])[CH3:2]참가 물질
4
반응 조건
- 온도
- 100 °C
실험 절차
To the suspension of 4-chloro-6-iodo-quinoline-3-carboxylic acid ethyl ester (example 1c, 1.5 g, 4.1 mmol) in anhydrous ethanol (25 mL) was added sodium ethoxide (0.7 g, 10.3 mol). The mixture was heated to 100° C. under a pressure tube and stirred for 4 h. After cooling to room temperature, the ice water was added. The solid was collected by filtration, washed with water and dried to obtain 6-iodo-4-ethoxy-quinoline-3-carboxylic acid ethyl ester (0.58 g, 38%) as a yellow solid. LC-MS m/e 372 (MH+)