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Dipropylamine → HCID 22908996, 화합물

HRID 1378979
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HRID 1378979 반응식
[CH3:1][O:2][C:3]1[CH:4]=[C:5]([S:31]([OH:34])(=O)=[O:32])[C:6](=[CH:27][C:28]=1[O:29][CH3:30])/[CH:7]=[CH:8]/[C:9]1[N:17]([CH3:18])[C:16]2[C:15](=[O:19])[N:14]([CH2:20][CH2:21][CH3:22])[C:13](=[O:23])[N:12]([CH2:24][CH2:25][CH3:26])[C:11]=2[N:10]=1.[CH2:35]([NH:38][CH2:39][CH2:40][CH3:41])[CH2:36][CH3:37]>>[CH2:35]([N:38]([CH2:39][CH2:40][CH3:41])[S:31]([C:5]1[C:6](=[CH:27][C:28]([O:29][CH3:30])=[C:3]([O:2][CH3:1])[CH:4]=1)/[CH:7]=[CH:8]/[C:9]1[N:17]([CH3:18])[C:16]2[C:15](=[O:19])[N:14]([CH2:20][CH2:21][CH3:22])[C:13](=[O:23])[N:12]([CH2:24][CH2:25][CH3:26])[C:11]=2[N:10]=1)(=[O:34])=[O:32])[CH2:36][CH3:37]
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

3

반응물 2

HCID 8902DipropylamineHCID 22909004HCID 22909004, 화합물

생성물 1

HCID 22908996HCID 22908996, 화합물수율 40%

실험 절차

Substantially the same procedure as in Example 2 was repeated using 1.00 g (1.96 mmol) of Compound 1 obtained in Example 1 and 2.68 ml (19.6 mmol) of dipropylamine. The resulting crude crystals were recrystallized from cyclohexane/toluene to give 450 mg (yield 40%) of Compound 3 as a pale yellow powder.

후처리

  1. customThe resulting crude crystals were recrystallized from cyclohexane/toluene

출처 및 근거

ORD 기록
ord-981e656ec6234176b527963ac9c58753
출처 데이터셋
uspto-grants-1997_09
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US05670498

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