Boron tribromide → 5-{[6-Fluoro-2-hydroxy-4,4-dimethyl-5-methoxy-2-(trifluoromethyl)-1,2,3,4-tetrahydronaphthalen-1-yl]amino}-2-methylphthalazin-1-one

반응식

[F:1][C:2]1[C:3]([O:20][CH3:21])=[C:4]([C:8]([CH3:19])([CH3:18])[CH2:9][C:10]([OH:17])([C:13]([F:16])([F:15])[F:14])[CH:11]=O)[CH:5]=[CH:6][CH:7]=1.[NH2:22][C:23]1[CH:32]=[CH:31][CH:30]=[C:29]2[C:24]=1[CH:25]=[N:26][N:27]([CH3:34])[C:28]2=[O:33].B(Br)(Br)Br>>[F:1][C:2]1[C:3]([O:20][CH3:21])=[C:4]2[C:5](=[CH:6][CH:7]=1)[CH:11]([NH:22][C:23]1[CH:32]=[CH:31][CH:30]=[C:29]3[C:24]=1[CH:25]=[N:26][N:27]([CH3:34])[C:28]3=[O:33])[C:10]([OH:17])([C:13]([F:14])([F:16])[F:15])[CH2:9][C:8]2([CH3:19])[CH3:18]

참가 물질

반응물 3

HCID 25134Boron tribromide

HCID 179850455-Amino-2-methylphthalazin-1-one

HCID 179890864-(3-Fluoro-2-methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal

생성물 1

HCID 686801705-{[6-Fluoro-2-hydroxy-4,4-dimethyl-5-methoxy-2-(trifluoromethyl)-1,2,3,4-tetrahydronaphthalen-1-yl]amino}-2-methylphthalazin-1-one수율 12.6%

실험 절차

Analogously to Example 10, the corresponding imine is produced starting from 200 mg of 4-(3-fluoro-2-methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)-pentanal and 114 mg of 5-amino-2-methyl-phthalazin-1-one. As in Example 2, 112 mg of imine is reacted by reaction with 0.36 ml of BBr3 (1 M in dichloromethane), and 38 mg of the title compound is obtained.