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Boron tribromide → 5-{[6-Fluoro-2 5-dihydroxy-4,4-dimethyl-2-(trifluoromethyl)-1,2,3,4-tetrahydronaphthalen-1-yl]amino}-2-methylphthalazin-1-one

HRID 1444481
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인쇄 미리보기

반응식

HRID 1444481 반응식
[F:1][C:2]1[C:3]([O:32]C)=[C:4]2[C:9](=[CH:10][CH:11]=1)[CH:8]([NH:12][C:13]1[CH:22]=[CH:21][CH:20]=[C:19]3[C:14]=1[CH:15]=[N:16][N:17]([CH3:24])[C:18]3=[O:23])[C:7]([OH:29])([C:25]([F:28])([F:27])[F:26])[CH2:6][C:5]2([CH3:31])[CH3:30].B(Br)(Br)Br>>[F:1][C:2]1[C:3]([OH:32])=[C:4]2[C:9](=[CH:10][CH:11]=1)[CH:8]([NH:12][C:13]1[CH:22]=[CH:21][CH:20]=[C:19]3[C:14]=1[CH:15]=[N:16][N:17]([CH3:24])[C:18]3=[O:23])[C:7]([OH:29])([C:25]([F:28])([F:26])[F:27])[CH2:6][C:5]2([CH3:30])[CH3:31]
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

3

반응물 2

HCID 25134Boron tribromideHCID 686801705-{[6-Fluoro-2-hydroxy-4,4-dimethyl-5-methoxy-2-(trifluoromethyl)-1,2,3,4-tetrahydronaphthalen-1-yl]amino}-2-methylphthalazin-1-one

생성물 1

HCID 875385635-{[6-Fluoro-2 5-dihydroxy-4,4-dimethyl-2-(trifluoromethyl)-1,2,3,4-tetrahydronaphthalen-1-yl]amino}-2-methylphthalazin-1-one수율 64%

실험 절차

29 mg of the compound of Example 69 is reacted analogously to Example 1 with 0.13 ml of BBr3 (1N in dichloromethane) to form 18 mg of the title compound.

출처 및 근거

ORD 기록
ord-a617efea720f4bc4829ed5b72a803877
출처 데이터셋
uspto-grants-2010_02
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07662821B2

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