Acetic Acid → HCID 20351305, 화합물

HRID 1448942노트

반응식

HRID 1448942 반응식
Cl[C:2]1[N:3]=[N:4][C:5]([O:8][C:9]2[CH:14]=[CH:13][C:12]([Cl:15])=[CH:11][CH:10]=2)=[CH:6][CH:7]=1.C(O)(=[O:18])C>>[Cl:15][C:12]1[CH:13]=[CH:14][C:9]([O:8][C:5]2[CH:6]=[CH:7][C:2](=[O:18])[NH:3][N:4]=2)=[CH:10][CH:11]=1

참가 물질

3

반응물 2

HCID 176Acetic AcidHCID 107525913-Chloro-6-(4-chlorophenoxy)pyridazine

생성물 1

HCID 20351305HCID 20351305, 화합물수율 80%

실험 절차

A solution of 10 g 3-chloro-6-(4-chlorophenoxy)-pyridazine in 100 ml acetic acid is maintained at reflux temperature for a few hours. The precipitate which appears on cooling is isolated and then recrystallised from butanol. There is thus obtained, at 80% yield, 6-(4-chlorophenoxy)-3-pyridazinone which melts at 202° C.

후처리

  1. temperatureat reflux temperature for a few hours
  2. temperatureon cooling
  3. customis isolated
  4. customrecrystallised from butanol

출처 및 근거

ORD 기록
ord-1e51472dd56c42e1bc87c3a7fbac3136
출처 데이터셋
uspto-grants-1980_02
특허 번호
US04188388

반응 노트

불러오는 중…