Sodium Iodide → HCID 14977896, 화합물

HRID 1449218노트

반응식

HRID 1449218 반응식
[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14]Br)=[CH:5][CH:4]=1.[I-:16].[Na+]>CC(=O)CC>[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][I:16])=[CH:5][CH:4]=1

참가 물질

4

실험 절차

6-(4-Methoxyphenyl)hexyl iodide [VIa; Ar is 4-CH3OC6H4, R is H] was prepared from 16.3 g. of 6-(4-methoxyphenyl)hexyl bromide (Preparation C11) and 9.93 g. of sodium iodide in 325 ml. of 2-butanone, to give 19.3 g. of product as a pale yellow oil.

출처 및 근거

ORD 기록
ord-cce3c89e0ea5437b8cdce92f2f5a0d0b
출처 데이터셋
uspto-grants-1980_02
특허 번호
US04189500

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