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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 1450생성일: 2026년 10월 23일

5-iodo-6-phenoxy-2-phenyl-4(3H)-pyrimidinone → 6-phenoxy-2-phenyl-4(3H)-pyrimidinone

https://huagongshe.com/ko/reaction/1450

반응식

참여 물질

역할이름HCID투입량
반응물5-iodo-6-phenoxy-2-phenyl-4(3H)-pyrimidinoneHCID 13185838—
촉매ZincHCID 23994—
용매Acetic AcidHCID 176—
생성물6-phenoxy-2-phenyl-4(3H)-pyrimidinoneHCID 13185841125.6%

반응 단계

A mixture of 7.07 g (18.1 mmol) of crude 5-iodo-6-phenoxy-2-phenyl-4(3H)-pyrimidinone, 2.02 g (31.1 mmol) of zinc dust and 25 mL of glacial acetic acid was heated to reflux. After 15 min an additional 2.06 g (31.7 mmol) of zinc dust was added, followed 15 min later by a further 2.04 g (31.4 mmol) of zinc dust. The mixture was maintained at reflux for 2 h, cooled and filtered to remove unreacted zinc. The filtrate was rotovaped to leave a semi-solid which was triturated with 75 mL of boiling water to afford 6.01 g (57% from 4,6-dihydroxy-2-phenylpyrimidine) of 6-phenoxy-2-phenyl-4(3H)-pyrimidinone as a yellow solid. 1H-NMR (d6-DMSO) δ 5.5(1H,s), 7.1-7.5(8H), 8.1(2H).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US05726124
출처 데이터셋uspto-grants-1998_03
ORD IDord-d6194f9ae43e4fbd94964245b6b3d3e4
출처 메모uspto-grants-1998_03