[OH-].[K+].[Cl:3][C:4]1[CH:5]=[C:6]2[C:10](=[CH:11][CH:12]=1)[C:9](=[O:13])[CH:8]([CH3:14])[C:7]2=[O:15].[Cl:16][C:17]1[N:22]=[C:21]([C:23]([CH2:25]Cl)=[CH2:24])[CH:20]=[CH:19][CH:18]=1>CO.[I-].[K+]>[Cl:3][C:4]1[CH:5]=[C:6]2[C:10](=[CH:11][CH:12]=1)[C:9](=[O:13])[C:8]([CH2:25][C:23]([C:21]1[CH:20]=[CH:19][CH:18]=[C:17]([Cl:16])[N:22]=1)=[CH2:24])([CH3:14])[C:7]2=[O:15]In 20 ml of methanol was dissolved 1.32 g of 85% potassium hydroxide, and then 3.89 g of 5-chloro-2-methylindan-1,3-dione, 3.76 g of 6-chloro-2-(1-chloromethylvinyl)pyridine and 0.05 g of potassium iodide were added to the solution. After refluxing under heating for 3 hours, the solvent was evaporated and water was poured. The reaction mixture was extracted with ethyl acetate, the organic layer was washed with water and with a saturated saline solution, and then dried over anhydrous magnesium sulfate. After the solvent was evaporated, the residue was separated and purified by silica gel column chromatography (developing solvent: n-hexane/ethyl acetate=5/1) to obtain 6.02 g of the compound No. 115 shown in Table 1.
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