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HRID 1596668생성일: 2026년 10월 26일

1-Chloro-4-morpholin-4-yl-2-naphthol → 4-Morpholino-2-naphthol

https://huagongshe.com/reaction/1596668

반응식

참여 물질

역할이름HCID투입량
반응물1-Chloro-4-morpholin-4-yl-2-naphtholHCID 609692—
촉매PalladiumHCID 23938—
용매EthanolHCID 702—
용매Sodium HydroxideHCID 14798—
생성물4-Morpholino-2-naphtholHCID 1098804277.8%

반응 단계

in a 0.3 l steel autoclave, 10.5 g of 1-chloro-4-morpholino-2-naphthol in 150 ml of sodium hydroxide (2N) and 30 ml of ethanol are maintained under a pressure of 3 bar and at 35° C. in the presence of 3 g of palladium on charcoal (5%) for 7 hours. The solution is then filtered to remove the catalyst. The aqueous phase is then acidified with acetic acid and then filtered. The precipitate is washed with water and then dried. 7.1 g of 4-morpholino-2-naphthol are thus obtained.

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US06291561B1
출처 데이터셋uspto-grants-2001_09
ORD IDord-9097480114864321971c9a53acc09a4f
출처 메모uspto-grants-2001_09