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Huagongshe화공사 화학 정보 인쇄 보고서 · 연구 참고용
HRID 16706생성일: 2026년 10월 23일

Sodium Bicarbonate → HCID 178501220, 화합물

https://huagongshe.com/ko/reaction/16706

반응식

참여 물질

역할이름HCID투입량
반응물Sodium BicarbonateHCID 516892—
반응물tert-butyl N-(2-oxoethyl)carbamateHCID 4247255—
반응물Sodium triacetoxyborohydrideHCID 5049666—
반응물HCID 178501210HCID 178501210—
용매DichloromethaneHCID 6344—
용매TriethylamineHCID 8471—
생성물HCID 178501220HCID 17850122042%

반응 단계

Methyl trans-4-aminocyclohexanecarboxylate hydrochloride (1.22 g) obtained in Reference Example 2(1) is suspended in dichloromethane (10 ml), and thereto is added triethylamine (1.76 ml) and the mixture is stirred for several minutes. After a solution of t-butyl (2-oxoethyl)carbamate (1.00 g) in dichloromethane (5 ml) and sodium triacetoxy borohydride (1.46 g) are added successively under ice-cooling, the reaction solution is warmed to the room temperature and stirred for 15 hours. Saturated aqueous sodium hydrogen carbonate solution is poured to the reaction solution, and the mixture is extracted with chloroform. The organic layer is dried over sodium sulfate and evaporated to remove the solvent under reduced pressure. A portion (1.71 g) of the resulting residue (2.33 g) is purified by silica gel column chromatography (eluent: chloroform/methanol=10/1) to give methyl trans-4-({2-[(t-butoxycarbonyl)amino]ethyl}amino)-cyclohexanecarboxylate (793 mg).

출처 및 근거

DOI10.6084/m9.figshare.5104873.v1
특허 번호US07737161B2
출처 데이터셋uspto-grants-2010_06
ORD IDord-a64d572eb4e34ab18c9971e3e2d6b989
출처 메모uspto-grants-2010_06