C(OC([NH:6][C:7]1[CH:12]=[CH:11][C:10]([NH:13]C(OCC)=O)=[C:9]([N+:19]([O-:21])=[O:20])[N:8]=1)=O)C.[OH-].[K+]>>[NH2:6][C:7]1[CH:12]=[CH:11][C:10]([NH2:13])=[C:9]([N+:19]([O-:21])=[O:20])[N:8]=14.0 g of the biscarbamate of Example 9 are boiled in 200 ml of an ethanolic 3 percent potassium hydroxide solution for 18 hours with reflux. This is followed by filtering and the filtrate is acidified with concentrated sulphuric acid, whereupon it is concentrated in vacuo. The residue is taken up in methanol. The desired product then crystallizes as hydrochloride (melting point 241° C.).
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