Benzamide → 4-Nitrobenzanilide

반응식

C(N)(=O)[C:2]1[CH:7]=[CH:6]C=[CH:4][CH:3]=1.[OH2:10].O.[OH-].[CH3:13][N+:14]([CH3:17])(C)C.[N+:18]([C:21]1[CH:26]=[CH:25][CH:24]=[CH:23][CH:22]=1)([O-:20])=[O:19]>>[N+:18]([C:21]1[CH:26]=[CH:25][C:24]([C:13]([NH:14][C:17]2[CH:6]=[CH:7][CH:2]=[CH:3][CH:4]=2)=[O:10])=[CH:23][CH:22]=1)([O-:20])=[O:19]

참가 물질

반응물 3

HCID 2331Benzamide

HCID 7416Nitrobenzene

HCID 22116808Tetramethylammonium hydroxide dihydrate

생성물 1

HCID 770034-Nitrobenzanilide수율 90%

실험 절차

A three-necked round-bottom flask equipped with a Dean-Strak trap and gas inlet line was charged with benzamide (0.2 mole), tetramethylammonium hydroxide dihydrate (0.2 mole) and nitrobenzene (100 mL). The reaction wasstirred for 8 hours at 65° C. with a continuous stream of air sweeping the surface of the reaction. Approximately 5 mL of water and 40 mL of nitrobenzene was collected in the Dean-Stark trap. Another 100 mL ofnitrobenzene was added and the reaction was allowed to stir overnight. A total of 70 mL of nitrobenzene was collected over this time period. The solution was cooled and water was added which caused the immediate precipitation of 4-nitrobenzanilide, i.e., N-(4-nitrophenyl)benzamide. Thesolution was filtered and a dark brown solid was obtained. The solid was washed with hot hexane and air dried to obtain 43.5 g of 4-nitrobenzanilide (90% yield).