Sodium Iodide → 4-(3-Iodopropoxy)benzoic acid, methyl ester
반응식
Cl[CH2:2][CH2:3][CH2:4][O:5][C:6]1[CH:15]=[CH:14][C:9]([C:10]([O:12][CH3:13])=[O:11])=[CH:8][CH:7]=1.[I-:16].[Na+]>CC(C)=O.C(OCC)C>[I:16][CH2:2][CH2:3][CH2:4][O:5][C:6]1[CH:15]=[CH:14][C:9]([C:10]([O:12][CH3:13])=[O:11])=[CH:8][CH:7]=1참가 물질
5
실험 절차
Dissolve 4-(3-chloropropoxy)benzoic acid, methyl ester (6.97 g, 30.5 mmol) in anhydrous acetone (100 mL) and add powdered sodium iodide (16.0 g, 107 mmol). Heat at reflux under an argon atmosphere for 38 hours. Dilute with ethyl ether (100 mL) and filter through Celite® filter aid. Wash the filtrate with water and brine, then dry (MgSO4). Evaporate the solvent in vacuo to give 4-(3-iodopropoxy)benzoic acid, methyl ester as a yellow oil.
후처리
- temperatureHeat
- temperatureat reflux under an argon atmosphere for 38 hours
- filtrationfilter through Celite®
- filtrationfilter aid
- washWash the filtrate with water and brine
- dry with materialdry (MgSO4)
- customEvaporate the solvent in vacuo
출처 및 근거
- ORD 기록
- ord-25af5a60b17f4f02b1428451900c7d5c
- 출처 데이터셋
- uspto-grants-1996_07
- 특허 번호
- US05541200
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