Hydrogen iodide → 4-Iodo-6-(2,3-difluoro-4-methoxyphenyl)pyrimidine

반응식

[F:1][C:2]1[C:7]([F:8])=[C:6]([O:9][CH3:10])[CH:5]=[CH:4][C:3]=1B(O)O.Cl[C:15]1[CH:20]=[C:19](Cl)[N:18]=[CH:17][N:16]=1.[IH:22]>>[I:22][C:15]1[CH:20]=[C:19]([C:3]2[CH:4]=[CH:5][C:6]([O:9][CH3:10])=[C:7]([F:8])[C:2]=2[F:1])[N:18]=[CH:17][N:16]=1

참가 물질

반응물 3

HCID 24841Hydrogen iodide

HCID 709434,6-Dichloropyrimidine

HCID 250672722,3-Difluoro-4-methoxybenzeneboronic acid

생성물 1

HCID 513550004-Iodo-6-(2,3-difluoro-4-methoxyphenyl)pyrimidine

실험 절차

The compound was prepared according to Example 1 using 2,3-difluoro-4-methoxyphenylboronic acid and 4,6-dichloropyrimidine. The resultant chloro compound was converted to iodo with hydroiodic acid as described in the general procedure.