Methanol → HCID 22768536, 화합물

HRID 1764488노트

반응식

HRID 1764488 반응식
[O:1]=[C:2]1[CH:6]([CH3:7])[O:5][CH:4]([CH3:8])[CH:3]1[C:9]([O:11][CH2:12][CH3:13])=[O:10].CO>C(O)C1C=CC=CC=1>[O:1]=[C:2]1[CH:6]([CH3:7])[O:5][CH:4]([CH3:8])[CH:3]1[C:9]([O:11][CH2:12][C:13]1[CH:7]=[CH:6][CH:2]=[CH:3][CH:4]=1)=[O:10]

참가 물질

4

실험 절차

40 g of 4-oxo-2,5-dimethyl-3-carboethoxytetrahydrofuran in 200 ml of benzyl alcohol are heated at 180°-200° C. The methanol formed is distilled off. The excess benzyl alcohol is distilled off under reduced pressure and the residue is fractionated. 45 g (corresponding to 78% of theory) of 4-oxo-2,5-dimethyl-3-carbobenzyloxytetrahydrofuran of boiling point 102° C/0.02 mm Hg and refractive index nD25 = 1.5070 are obtained.

후처리

  1. distillationis distilled off
  2. distillationThe excess benzyl alcohol is distilled off under reduced pressure

출처 및 근거

ORD 기록
ord-fcaffd7d8da140538ac716f8d8dcf6fe
출처 데이터셋
uspto-grants-1978_09
특허 번호
US04116982

반응 노트

불러오는 중…