2-Cyclopropyl-5-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)isoindolin-1-one → HCID 76285364, 화합물

HRID 1778694노트

반응식

HRID 1778694 반응식
[Cl:1][C:2]1[C:7]([O:8][CH3:9])=[CH:6][C:5]([O:10][CH3:11])=[C:4]([Cl:12])[C:3]=1[C:13]1[N:18]=[CH:17][C:16]2[C:19](I)=[N:20][NH:21][C:15]=2[CH:14]=1.[CH:23]1([N:26]2[CH2:34][C:33]3[C:28](=[CH:29][CH:30]=[C:31](B4OC(C)(C)C(C)(C)O4)[CH:32]=3)[C:27]2=[O:44])[CH2:25][CH2:24]1>>[CH:23]1([N:26]2[CH2:34][C:33]3[C:28](=[CH:29][CH:30]=[C:31]([C:19]4[C:16]5[CH:17]=[N:18][C:13]([C:3]6[C:2]([Cl:1])=[C:7]([O:8][CH3:9])[CH:6]=[C:5]([O:10][CH3:11])[C:4]=6[Cl:12])=[CH:14][C:15]=5[NH:21][N:20]=4)[CH:32]=3)[C:27]2=[O:44])[CH2:25][CH2:24]1

참가 물질

3

반응물 2

HCID 594023502-Cyclopropyl-5-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)isoindolin-1-oneHCID 1784934546-(2,6-dichloro-3,5-dimethoxyphenyl)-3-iodo-1H-pyrazolo[4,3-c]pyridine

생성물 1

HCID 76285364HCID 76285364, 화합물

실험 절차

This compound was prepared by using procedures analogous to those described for the synthesis of Example 4, Step 2 starting from 6-(2,6-dichloro-3,5-dimethoxyphenyl)-3-iodo-1H-pyrazolo[4,3-c]pyridine and 2-cyclopropyl-5-(4,4,5,5-tetramethyl-1,3,2-dioxaborolan-2-yl)isoindolin-1-one (Example 21, Step 2). LCMS (M+H)+=495.1/497.1.

후처리

  1. customThis compound was prepared

출처 및 근거

ORD 기록
ord-e9478c7b6772464e8404260a944f0021
출처 데이터셋
uspto-grants-2016_02
특허 번호
US09266892B2

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