Isopropyl iodide → 2-Chloro-4-isopropoxybenzoic Acid

HRID 1816652

반응식

[Cl:1][C:2]1[CH:11]=[C:10]([OH:12])[CH:9]=[CH:8][C:3]=1[C:4]([O:6]C)=[O:5].[CH:13](I)([CH3:15])[CH3:14]>>[Cl:1][C:2]1[CH:11]=[C:10]([O:12][CH:13]([CH3:15])[CH3:14])[CH:9]=[CH:8][C:3]=1[C:4]([OH:6])=[O:5]

참가 물질

반응물 2

HCID 6362Isopropyl iodide

HCID 134988302-Chloro-4-hydroxy-benzoic acid methyl ester

생성물 1

HCID 224940892-Chloro-4-isopropoxybenzoic Acid

실험 절차

Using methyl 2-chloro-4-hydroxybenzoate and isopropyl iodide, 2-chloro-4-isopropoxybenzoic acid was obtained in the same method as in Production Example 277b).

출처 및 근거

ORD 기록: ord-42b087c1afd845279e52137942b5c2bd
출처 데이터셋: uspto-grants-2005_04
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US06884821B1

연결된 노트

불러오는 중…