2-Fluoro-4-nitrophenol → HCID 21920028, 화합물

HRID 1823006노트

반응식

HRID 1823006 반응식
[F:1][C:2]1[CH:7]=[C:6]([N+:8]([O-:10])=[O:9])[CH:5]=[CH:4][C:3]=1[OH:11].C(=O)([O-])[O-].[K+].[K+].[F:18][C:19]1[CH:20]=[C:21]([CH:24]=[CH:25][CH:26]=1)[CH2:22]Br>CC(CC)=O.O>[F:1][C:2]1[CH:7]=[C:6]([N+:8]([O-:10])=[O:9])[CH:5]=[CH:4][C:3]=1[O:11][CH2:22][C:21]1[CH:24]=[CH:25][CH:26]=[C:19]([F:18])[CH:20]=1

참가 물질

6

반응물 3

HCID 98252-Fluoro-4-nitrophenolHCID 11430Potassium CarbonateHCID 680073-Fluorobenzyl bromide

생성물 1

HCID 21920028HCID 21920028, 화합물

시약·촉매·용매 2

HCID 962Water용매HCID 6569Methyl Ethyl Ketone용매

실험 절차

A mixture of 10.0 g (63.7 mmol) 2-fluoro-4-nitrophenol, 17.6 g (127 mmol) potassium carbonate and 13.24 g (70.0 mmol) 3-fluorobenzyl bromide in 200 ml ethyl methyl ketone is hold overnight at 80° C. The reaction mixture is diluted with water and extracted with ethyl acetate. Crystallisation from diethyl ether/n-hexane gives 12.68 g (75%) of a slightly yellow solid. MS: m/e=265.1 (M+).

후처리

  1. extractionextracted with ethyl acetate
  2. customCrystallisation from diethyl ether/n-hexane
  3. customgives 12.68 g (75%) of a slightly yellow solid

출처 및 근거

ORD 기록
ord-99cad2cdbdf942cf8487db56b3f13cf2
출처 데이터셋
uspto-grants-2006_05
특허 번호
US07037935B2

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