Bisphenol B → Bisphenol E
반응식
C[CH2:2][C:3]([C:12]1[CH:17]=[CH:16][C:15]([OH:18])=[CH:14][CH:13]=1)([C:5]1[CH:10]=[CH:9][C:8]([OH:11])=[CH:7][CH:6]=1)C>C(Cl)Cl>[CH3:2][CH:3]([C:5]1[CH:10]=[CH:9][C:8]([OH:11])=[CH:7][CH:6]=1)[C:12]1[CH:13]=[CH:14][C:15]([OH:18])=[CH:16][CH:17]=1참가 물질
3
시약·촉매·용매 1
실험 절차
A methylene chloride solution of a bisphenol B oligomer having a chloroformate group at its molecular terminal was obtained in the same manner as that in Manufacturing Example 1 except that the bisphenol E was replaced by 65.8 g (0.272 mol) of 2,2-bis(4-hydroxyphenyl)butane (BisB), the amount of triethylamine was changed to 53.8 g (0.533 mol), and the methylene chloride solution of phosgene was replaced by a solution in which 52.7 g (0.533 mol) of phosgene was dissolved in 225 mL of methylene chloride in Manufacturing Example 1. The obtained solution had a chloroformate concentration of 0.99 mol/L, a solid concentration of 0.21 kg/L and an average number of repeating units (n′) of 1.21. A content of an amide compound in the obtained BisB oligomer was found to be 90 mass ppm. A mass of nitrogen derived from triethylamine was 0.3 mass ppm. This obtained ingredient will be referred to as “BisB-CF” hereinafter.