[Cl:1][C:2]1[CH:3]=[C:4]([N:8]2[C:12]([C:13]3[CH:18]=[C:17]([C:19]([F:22])([F:21])[F:20])[CH:16]=[C:15]([F:23])[CH:14]=3)=[CH:11][C:10]([C:24]([O:26]CC)=[O:25])=[N:9]2)[CH:5]=[CH:6][CH:7]=1.ClC1C=C(N2C(C3C=C(F)C=C(Cl)C=3)=CC(C(O)=O)=N2)C=CC=1F>>[Cl:1][C:2]1[CH:3]=[C:4]([N:8]2[C:12]([C:13]3[CH:18]=[C:17]([C:19]([F:22])([F:21])[F:20])[CH:16]=[C:15]([F:23])[CH:14]=3)=[CH:11][C:10]([C:24]([OH:26])=[O:25])=[N:9]2)[CH:5]=[CH:6][CH:7]=1The preparation of the title compound takes place starting from the compound of Example 49A in analogy to the synthesis of the compound of Example 71A. 1.82 g (85% of theory) of the title compound are obtained.
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