4-(Chloromethyl)pyridinium chloride → HCID 21994450, 화합물

HRID 1977605

반응식

HRID 1977605 반응식
[CH2:1]1[C:9]2[C:4](=[CH:5][CH:6]=[CH:7][CH:8]=2)[CH2:3][CH:2]1[O:10][C:11]1[CH:12]=[C:13]([CH:22]=[CH:23][C:24]=1[O:25][CH3:26])[NH:14][C:15]1[CH2:19][CH2:18][C:17](=[O:20])[C:16]=1[CH3:21].Cl.Cl[CH2:29][C:30]1[CH:35]=[CH:34][N:33]=[CH:32][CH:31]=1>>[CH2:1]1[C:9]2[C:4](=[CH:5][CH:6]=[CH:7][CH:8]=2)[CH2:3][CH:2]1[O:10][C:11]1[CH:12]=[C:13]([CH:22]=[CH:23][C:24]=1[O:25][CH3:26])[N:14]([C:15]1[CH2:19][CH2:18][C:17](=[O:20])[C:16]=1[CH3:21])[CH2:29][C:30]1[CH:35]=[CH:34][N:33]=[CH:32][CH:31]=1

참가 물질

3

반응물 2

HCID 745704-(Chloromethyl)pyridinium chlorideHCID 98631853-[3-(2-Indanyloxy)-4-methoxyanilino]-2-methyl-2-cyclopenten-1-one

생성물 1

HCID 21994450HCID 21994450, 화합물수율 38.8%

실험 절차

According to the same procedure as in Example 28, using 3-[3-(2-indanyloxy)-4-methoxyanilino]-2-methyl-2-cyclopenten-1-one produced in Example 10 instead of 3-(3-cyclopentyloxy-4-methoxyanilino)-2-cyclopenten-1-one, and using 4-(chloromethyl)pyridine hydrochloride instead of methyl iodide, the title compound (yield 38.8%) was obtained as a brown oil.

출처 및 근거

ORD 기록
ord-64ee173c34894fd386fa3d87085d74ed
출처 데이터셋
uspto-grants-2001_05
특허 번호
US06235736B1

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