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5-Bromo-2-oxindole → HCID 25207489, 화합물

HRID 2068724
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HRID 2068724 반응식
[OH:1][C@H:2]([CH2:17][N:18]1[CH2:23][CH2:22][O:21][CH2:20][CH2:19]1)[CH2:3][N:4]1[CH2:9][CH2:8][C:7]2[NH:10][C:11]([CH:14]=O)=[C:12]([CH3:13])[C:6]=2[C:5]1=[O:16].[Br:24][C:25]1[CH:26]=[C:27]2[C:31](=[CH:32][CH:33]=1)[NH:30][C:29](=[O:34])[CH2:28]2>>[Br:24][C:25]1[CH:26]=[C:27]2[C:31](=[CH:32][CH:33]=1)[NH:30][C:29](=[O:34])/[C:28]/2=[CH:14]\[C:11]1[NH:10][C:7]2[CH2:8][CH2:9][N:4]([CH2:3][C@H:2]([OH:1])[CH2:17][N:18]3[CH2:19][CH2:20][O:21][CH2:22][CH2:23]3)[C:5](=[O:16])[C:6]=2[C:12]=1[CH3:13]
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

3

반응물 2

HCID 6111935-Bromo-2-oxindoleHCID 59375987HCID 59375987, 화합물

생성물 1

HCID 25207489HCID 25207489, 화합물수율 50%

실험 절차

The title compound was prepared under the same conditions as described in step 6 of Example 1 with (R)-5-(2-hydroxy-3-morpholin-4-yl-propyl)-3-methyl-4-oxo-4,5,6,7-tetrahydro-1H-pyrrolo[3,2-c]pyridine-2-carbaldehyde 1f obtained from step 5 of Example 1 and 5-bromo-1,3-dihydro-indol-2-one as starting materials to give (R,Z)-2-(5-bromo-2-oxo-1,2-dihydro-indol-3-ylidenemethyl)-5-(2-hydroxy-3-morpholin-4-yl-propyl)-3-methyl-1,5,6,7-tetrahydro-pyrrolo[3,2-c]pyridin-4-one 4 (24 mg, yield 50%) as a yellow solid.

후처리

  1. customThe title compound was prepared under the same conditions

출처 및 근거

ORD 기록
ord-a54474cd89944dd2884ff01c190a5243
출처 데이터셋
uspto-grants-2012_10
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US08299069B2

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