반응식
[Cl:1][C:2]1[CH:3]=[C:4]([CH:18]=[CH:19][C:20]=1[O:21][CH3:22])[C:5]([NH:7][C:8]1[CH:17]=[CH:16][CH:15]=[CH:14][C:9]=1[C:10]([O:12]C)=[O:11])=[O:6].CO>C1COCC1.O>[Cl:1][C:2]1[CH:3]=[C:4]([CH:18]=[CH:19][C:20]=1[O:21][CH3:22])[C:5]([NH:7][C:8]1[CH:17]=[CH:16][CH:15]=[CH:14][C:9]=1[C:10]([OH:12])=[O:11])=[O:6]참가 물질
5
실험 절차
A solution of 42A (340 mg, 1.1 mmol) in THF (30 mL)/MeOH (10 mL) was treated with a solution of LiOH monohydrate (223 mg, 5.3 mmol) in water (10 mL). The reaction was stirred for 24 hours at room temperature and concentrated to a yellow solid. The crude acid was dissolved in water (100 mL) and acidified with 1 N HCl to pH 4. The resulting solid was collected by vacuum filtration and washed with water (2×100 mL) to afford 42B (260 mg, 85%).
후처리
- concentrationconcentrated to a yellow solid
- dissolutionThe crude acid was dissolved in water (100 mL)
- filtrationThe resulting solid was collected by vacuum filtration
- washwashed with water (2×100 mL)
출처 및 근거
- ORD 기록
- ord-9fc9c0e848184a03a5202cc664e60239
- 출처 데이터셋
- uspto-grants-2009_08
- 특허 번호
- US07569725B2
연결된 노트
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