[Cl:1][C:2]1[C:9]([O:10][CH3:11])=[C:8]([O:12][CH3:13])[CH:7]=[CH:6][C:3]=1[CH:4]=O.C(O)(=O)[CH2:15][C:16]([OH:18])=[O:17]>>[Cl:1][C:2]1[C:9]([O:10][CH3:11])=[C:8]([O:12][CH3:13])[CH:7]=[CH:6][C:3]=1[CH:4]=[CH:15][C:16]([OH:18])=[O:17]Similar procedure as described in example 9B was used, starting from 2-Chloro-3,4-dimethoxy-benzaldehyde and malonic acid to give 3-(2-Chloro-3,4-dimethoxy-phenyl)-acrylic acid. LC-MS: m/e 241 (M−1).
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