[Cl:1][C:2]1[C:7]([O:8][CH3:9])=[C:6]([O:10][CH3:11])[CH:5]=[CH:4][C:3]=1[CH:12]=[CH:13][C:14]([OH:16])=[O:15]>[Pd]>[Cl:1][C:2]1[C:7]([O:8][CH3:9])=[C:6]([O:10][CH3:11])[CH:5]=[CH:4][C:3]=1[CH2:12][CH2:13][C:14]([OH:16])=[O:15]Similar procedure as described in example 9B was used, starting from 3-(2-Chloro-3,4-dimethoxy-phenyl)-acrylic acid and Pd—C to give 3-(2-Chloro-3,4-dimethoxy-phenyl)-propionic acid. LC-MS: m/e 243 (M−1).
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