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1-(2-Pyrimidinyl)piperazine → 4-Chloro-7-(1-(tert-butoxycarbonyl)-5-[4-(pyrimidin-2-yl)piperazin-1-ylmethyl]indol-2-yl)isoindolinone

HRID 21060
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인쇄 미리보기

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HRID 21060 반응식
[Cl:1][C:2]1[CH:10]=[CH:9][C:8]([C:11]2[N:12]([C:22]([O:24][C:25]([CH3:28])([CH3:27])[CH3:26])=[O:23])[C:13]3[C:18]([CH:19]=2)=[CH:17][C:16]([CH:20]=O)=[CH:15][CH:14]=3)=[C:7]2[C:3]=1[CH2:4][NH:5][C:6]2=[O:29].[N:30]1[CH:35]=[CH:34][CH:33]=[N:32][C:31]=1[N:36]1[CH2:41][CH2:40][NH:39][CH2:38][CH2:37]1.C(O[BH-](OC(=O)C)OC(=O)C)(=O)C.[Na+]>ClCCl>[Cl:1][C:2]1[CH:10]=[CH:9][C:8]([C:11]2[N:12]([C:22]([O:24][C:25]([CH3:26])([CH3:27])[CH3:28])=[O:23])[C:13]3[C:18]([CH:19]=2)=[CH:17][C:16]([CH2:20][N:39]2[CH2:40][CH2:41][N:36]([C:31]4[N:30]=[CH:35][CH:34]=[CH:33][N:32]=4)[CH2:37][CH2:38]2)=[CH:15][CH:14]=3)=[C:7]2[C:3]=1[CH2:4][NH:5][C:6]2=[O:29]
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

5

반응물 3

HCID 887471-(2-Pyrimidinyl)piperazineHCID 5049666Sodium triacetoxyborohydrideHCID 866282274-Chloro-7-[1-(tert-butoxycarbonyl)-5-formylindol-2-yl]isoindolinone

생성물 1

HCID 684916624-Chloro-7-(1-(tert-butoxycarbonyl)-5-[4-(pyrimidin-2-yl)piperazin-1-ylmethyl]indol-2-yl)isoindolinone

시약·촉매·용매 1

HCID 6344Dichloromethane
용매

실험 절차

In a similar manner to Step 1 of Example 56, 4-chloro-7-[1-(tert-butoxycarbonyl)-5-formylindol-2-yl]isoindolinone (20.0 mg, 0.0487 mmol) was dissolved in dichloromethane (0.5 mL). The solution was treated with 1-(2-pyrimidyl)piperazine (33 mg, 0.20 mmol) and sodium triacetoxyborohydride (32 mg, 0.15 mmol) to obtain 4-chloro-7-(1-(tert-butoxycarbonyl)-5-[4-(pyrimidin-2-yl)piperazin-1-ylmethyl]indol-2-yl)isoindolinone.

출처 및 근거

ORD 기록
ord-44ad9a8143d54eb9950b96aa145e691b
출처 데이터셋
uspto-grants-2010_06
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07745641B2

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