Sulfuric Acid → 6-Bromo-4'-methoxyflavone
반응식
[Br:1][C:2]1[CH:3]=[CH:4][C:5]([OH:21])=[C:6]([C:8](=[O:20])[CH2:9][C:10]([C:12]2[CH:17]=[CH:16][C:15]([O:18][CH3:19])=[CH:14][CH:13]=2)=O)[CH:7]=1.S(=O)(=O)(O)O>C(O)(=O)C>[Br:1][C:2]1[CH:7]=[C:6]2[C:5](=[CH:4][CH:3]=1)[O:21][C:10]([C:12]1[CH:13]=[CH:14][C:15]([O:18][CH3:19])=[CH:16][CH:17]=1)=[CH:9][C:8]2=[O:20]참가 물질
4
실험 절차
A mixed solution consisting of compound 14 (2.67 g, 7.65 mmol), concentrated sulfuric acid (0.78 ml), and acetic acid (40 ml) was heated to reflux for 1 hour. The temperature of the resultant was returned to room temperature, and ice pieces were then added to the reaction solution. The precipitated crystal was collected by filtration, so as to obtain a product of interest, 6-bromo-4′-methoxyflavone (compound 15). Yield: 2.01 g (yield constant: 79.4%) 1H NMR (300 MHz, CDCl3) δ8.35 (s, 1H), 7.87 (d, J=9.0 Hz, 2H), 7.77 (d, J=9.0 Hz, 1H), 7.45 (d, J=9.3 Hz, 1H), 7.03 (d, J=9.0 Hz, 2H), 6.75 (s, 1H), 3.90 (s, 3H).