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Aluminium lithium hydride → [3-Chloro-5-(4-methoxyphenyl)-1,2-thiazol-4-yl]methanol

HRID 2177270
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HRID 2177270 반응식
[Cl:1][C:2]1[C:6]([C:7](OC)=[O:8])=[C:5]([C:11]2[CH:16]=[CH:15][C:14]([O:17][CH3:18])=[CH:13][CH:12]=2)[S:4][N:3]=1.[H-].[H-].[H-].[H-].[Li+].[Al+3]>O1CCCC1>[Cl:1][C:2]1[C:6]([CH2:7][OH:8])=[C:5]([C:11]2[CH:16]=[CH:15][C:14]([O:17][CH3:18])=[CH:13][CH:12]=2)[S:4][N:3]=1
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참가 물질

4

반응물 2

HCID 21226445Aluminium lithium hydrideHCID 90418689Methyl 3-chloro-5-(4-methoxyphenyl)-1,2-thiazole-4-carboxylate

생성물 1

HCID 90418060[3-Chloro-5-(4-methoxyphenyl)-1,2-thiazol-4-yl]methanol

시약·촉매·용매 1

HCID 8028Tetrahydrofuran용매

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온도
0 °C

실험 절차

Into a 25-mL round-bottom flask (1 atm) purged and maintained with an inert atmosphere of nitrogen, was placed methyl 3-chloro-5-(4-methoxyphenyl)-1,2-thiazole-4-carboxylate (450 mg, 1.59 mmol, 1.00 equiv), tetrahydrofuran (25 mL). This was followed by the addition of LAH (90 mg, 2.37 mmol, 1.50 equiv), in portions at 0° C. The resulting solution was stirred for 30 min at 0° C. in a water/ice bath. The reaction was then quenched by the addition of 2 mL of MeOH. The resulting mixture was concentrated under vacuum. The residue was applied onto a silica gel column with ethyl acetate/petroleum ether (20/80). This resulted in 223 mg (55%) of [3-chloro-5-(4-methoxyphenyl)-1,2-thiazol-4-yl]methanol as a light yellow solid.

후처리

  1. customInto a 25-mL round-bottom flask (1 atm) purged
  2. temperaturemaintained with an inert atmosphere of nitrogen
  3. customThe reaction was then quenched by the addition of 2 mL of MeOH
  4. concentrationThe resulting mixture was concentrated under vacuum
  5. customThis resulted in 223 mg (55%) of [3-chloro-5-(4-methoxyphenyl)-1,2-thiazol-4-yl]methanol as a light yellow solid

출처 및 근거

ORD 기록
ord-4284a52e85764037a0b8384897f7fac9
출처 데이터셋
uspto-grants-2015_06
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US09067898B1

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