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1-Iodopropane → HCID 11430582, 화합물

HRID 2218035
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HRID 2218035 반응식
[CH3:1][O:2][C:3]1[C:4]([C:23]2[CH:28]=[CH:27][CH:26]=[CH:25][C:24]=2[O:29][CH3:30])=[CH:5][C:6]2[C:12]([C:13]3[CH:14]=[C:15]([CH:18]=[CH:19][CH:20]=3)[C:16]#[N:17])=[N:11][CH2:10][C:9](=[O:21])[NH:8][C:7]=2[CH:22]=1.[CH2:31](I)[CH2:32][CH3:33]>>[CH3:1][O:2][C:3]1[C:4]([C:23]2[CH:28]=[CH:27][CH:26]=[CH:25][C:24]=2[O:29][CH3:30])=[CH:5][C:6]2[C:12]([C:13]3[CH:14]=[C:15]([CH:18]=[CH:19][CH:20]=3)[C:16]#[N:17])=[N:11][CH2:10][C:9](=[O:21])[N:8]([CH2:31][CH2:32][CH3:33])[C:7]=2[CH:22]=1
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

3

반응물 2

HCID 336431-IodopropaneHCID 114863203-[8-Methoxy-7-(2-methoxy-phenyl)-2-oxo-2,3-dihydro-1H-benzo[e][1,4]diazepin-5-yl]-benzonitrile

생성물 1

HCID 11430582HCID 11430582, 화합물수율 89%

실험 절차

Prepared from 3-[8-methoxy-7-(2-methoxy-phenyl)-2-oxo-2,3-dihydro-1H-benzo[e][1,4]diazepin-5-yl]-benzonitrile Example 10 using the same method described for Example 35 using propyl iodide instead of hexyl bromine. The title compound (99 mg) was obtained as a white solid, yield=89%.

출처 및 근거

ORD 기록
ord-a878b1e16e3148eb9254ff24cd7addc2
출처 데이터셋
uspto-grants-2008_08
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07410963B2

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