p-Fluoronitrobenzene → HCID 23725483, 화합물

HRID 2219344노트

반응식

[F:1][C:2]1[CH:3]=[C:4]([C:9]2[C:13]([C:14]3[N:15]=[CH:16][NH:17][CH:18]=3)=[C:12]([CH3:19])[O:11][N:10]=2)[CH:5]=[CH:6][C:7]=1[F:8].F[C:21]1[CH:26]=[CH:25][C:24]([N+:27]([O-:29])=[O:28])=[CH:23][CH:22]=1>>[F:1][C:2]1[CH:3]=[C:4]([C:9]2[C:13]([C:14]3[N:15]=[CH:16][N:17]([C:21]4[CH:26]=[CH:25][C:24]([N+:27]([O-:29])=[O:28])=[CH:23][CH:22]=4)[CH:18]=3)=[C:12]([CH3:19])[O:11][N:10]=2)[CH:5]=[CH:6][C:7]=1[F:8]

참가 물질

반응물 2

HCID 9590p-Fluoronitrobenzene

HCID 178435006HCID 178435006, 화합물

생성물 1

HCID 23725483HCID 23725483, 화합물수율 76%

실험 절차

As described for Example 53, 3-(3,4-difluoro-phenyl)-4-(1H-imidazol-4-yl)-5-methyl-isoxazole (78 mg, 0.3 mmol) using 1-fluoro-4-nitrobenzene instead of 4-fluoroacetophenone was converted to the title compound (89 mg, 76%) which was obtained as a light yellow solid. MS: m/e=383.1 [M+H]+.

출처 및 근거

ORD 기록: ord-b35107fe9d8b4689a89b727008eb9df2
출처 데이터셋: uspto-grants-2008_08
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US07414061B2

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