[Br:1][C:2]1[CH:3]=[C:4]([CH3:9])[C:5]([Cl:8])=[N:6][CH:7]=1.[Br:10]C1C(CBr)=NC(Cl)=CC=1>>[Br:1][C:2]1[CH:3]=[C:4]([CH2:9][Br:10])[C:5]([Cl:8])=[N:6][CH:7]=1Compound 76B (0.46 g, 33%) was prepared from 76A (1.0 g, 4.9 mmol) using a procedure similar to the synthesis of 55B.
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